5x^2+2x=4-x

Solution for 5x^2+2x=4-x equation:

5x^2+2x=4-x

We move all terms to the left:

5x^2+2x-(4-x)=0

We add all the numbers together, and all the variables

5x^2+2x-(-1x+4)=0

We get rid of parentheses

5x^2+2x+1x-4=0

We add all the numbers together, and all the variables

5x^2+3x-4=0

a = 5; b = 3; c = -4;
Δ = b2-4ac
Δ = 32-4·5·(-4)
Δ = 89
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-\sqrt{89}}{2*5}=\frac{-3-\sqrt{89}}{10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+\sqrt{89}}{2*5}=\frac{-3+\sqrt{89}}{10}
$